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X^2-3X=12-4X
We move all terms to the left:
X^2-3X-(12-4X)=0
We add all the numbers together, and all the variables
X^2-3X-(-4X+12)=0
We get rid of parentheses
X^2-3X+4X-12=0
We add all the numbers together, and all the variables
X^2+X-12=0
a = 1; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·1·(-12)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*1}=\frac{-8}{2} =-4 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*1}=\frac{6}{2} =3 $
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